信号是携带数据的电流或电磁电流,可以传输或接收。
在数学上表示为自变量的函数,例如密度、深度等。因此,信号是随时间、空间或可以传达信息的任何其他自变量而变化的物理量。这里的自变量是时间。
时间信号的类型:
连续时间信号 x(t)-在每个时间点定义
离散时间信号 x[n] –仅在一组离散的时间值(整数)处定义。
系统是任何一组物理组件或多个设备的功能,它们将信号输入并产生信号作为输出。
模拟信号
信号可以是模拟量,这意味着它是根据时间定义的。这是一个连续的信号。这些信号是在连续自变量上定义的。它们很难分析,因为它们带有大量的值。由于大量的值样本,它们非常准确。为了存储这些信号,您需要无限的内存,因为它可以在实线上实现无限的值。模拟信号用正弦波表示。
数字信号
与模拟信号相比,数字信号非常容易分析。它们是不连续的信号。它们是模拟信号的挪用。
数字这个词代表离散值,因此这意味着它们使用特定值来表示任何信息。在数字信号中,只有两个值用于表示某事,即:1 和 0(二进制值)。数字信号不如模拟信号准确,因为它们是在一段时间内获取的模拟信号的离散样本。然而,数字信号不受噪声影响。因此它们持续时间长且易于解释。数字信号用方波表示。
模拟信号和数字信号的区别
比较元素 | 模拟信号 | 数字信号 |
分析 | 难的 | 可分析 |
表示 | 连续的 | 不连续 |
准确性 | 更准确的 | 不太准确 |
贮存 | 无限记忆 | 易于存储 |
受噪音影响 | 是的 | 不 |
录音技术 | 保留原始信号 | 采集并保存信号样本 |
例子 | 人声、温度计、模拟电话等 | 电脑、数码电话、数码笔等 |
信号与系统的代写高分代写案例
Question 1
- I am a non-zero continuous-time signal x. When you use me as an input signal to a stable linear time-invariant system then the output signal will be myself times a constant complex number. Who am I? Explain your answer-but no proofs are needed.
- Consider a continuous-time system given by the equation
y ⑴=sin(tXt),
where v denotes the input signal and y denotes the output signal.
- Is this system linear time-invariant? If “no”, which property is missing: “linearity” or “time-invariance”, or both——explain your answers. If “yes”, give a proof.
- Consider the response y to the input signal v given by v(t) = cost Show that y can be expressed as = 6cos(u;of — </>), where b,必 and <p are positive real numbers and where (p < 2兀;be sure to give the numerical values of b, and 0.
- Explain how your answer in (ii) can be used to answer (i).
- Consider an ideal filter with frequency response
1 0 < |cu| <
0 otherwise ‘
where 3c is a positive real number. Consider the output signal y that is the response of this filter to the periodic input signal v from part (b). For S =开/3 it can be shown that the signal y can be written as
y(t) = & + K2cos(δ),
where K? and a are real numbers. Determine K],K2 and a.
- Repeat (c) for = tt/8.
- Repeat (c) for ljc = 2tt/3.
- [Consider the wave w given by
oo
w(t) = g[t — 81) for all i G R,
1——OQ
with g defined for alU 6 R as
W = J 4 -2 < t < 0
0 [ 0 otherwise.
Repeat part (b) for this wave w.
- Which of the following discrete lime signals are periodic? No explanations are needed; there can be zero, one or more than one answer.
- x[n) = cos(7rn)
- x(n) – cos(n\/5)
- x(n) — cos(n\/5) + cos(7T7i)
- x(n) — cos(n\/5) + cos(2n\/5)
- Which of the following continuous time signals are periodic? No explanations are needed; there can be zero, one or more than one answer.
- x(t) = C0S(7Tf)
- x(t) = cos(t\/5)
- x(t) = cos(t\/5) + cos(7rt)
- x(t) = cos(t\/5) + cos(2t\/5)
Question 2
In this question 6 denotes the discrete-time unit pulse signal:
J(n) = | [0 otherwise.
- 11 mark] Consider the discrete-time signal x, defined for all n e Z, given by
x(n\ = J 1 九=123
[0 otherwise.
Further define the discrete-time signal y by
y(n) = x(n) + x(—n) + d(n).
Sketch y and make sure that you indicate relevant values in your plot.
- Plot the signal where denotes discrete-time convolution and x and y are as in (a). Make sure that you indicate relevant values in your plot.
- Let x be as in part (a). Consider the system that has x as its unit pulse response. Compute the system’s step response.